Consider the following program:
s="IISER"
print s.count("I")Output- 2
which was expected.
However consider this-
s="IISER"
print s.count("")Output- 6
Why did we get 6 when there are only 5 characters?
Hint : This answer can be got to by trying to emulate count() without inbuilt functions.
I tried emulating, and all this program returned was: 0
def countchar(S, s):
# S is string to be examined, s is the character to be counted.
count = 0
for let in S:
if(let == s):
count +=1
return count
print countchar("IISER", "")
You have misunderstood the definition of super.count(sub). It counts the number of occurrences of the sub-string sub in the string super.
There are 6 (count them!) occurrences of the empty string in the string "super".
Try to write the correct program to do what count does.
I believe it initiates the first " " before the first "I", because it is the default string, so it considers the empty character as an extra subset. I might be wrong, however.
Can you further elaborate on
initiates the first " " before the first "I", because it is the default stringAlso please give 1 or 2 outputs too.
Further, can you extend the program to take a substring of any size? (Presently you've only considered that the substring is only a single letter)